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Question

The 17th term of an AP exceeds its 10th term by 7. The common difference is 2.


A
1
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B
False
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Solution

The correct option is B False

It is given that 17th term exceeds its 10th term by 7
It means a17 = a10 + 7......(1)
Here, a17 is the 17th term and a10 is the 10th term of an AP.
Using formula an=a+(n1)d to find nth term of arithmetic progression, we get

a17 =a+(16)d .....(2)

a10 = a+(9)d .....(3)

Putting (2) and (3) in equation (1), we get

a+16d=a+9d+7

7d=7

d=77=1


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