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Question

The 17th term of an AP exceeds its 10th term by 21. The common difference of the AP is
(a) 3
(b) 2
(c) −3
(d) −2


Solution

( a) 3
T10 = a + 9d   
T17 = a + 16d 

Also, a + 16d = 21 + T10
     ⇒ a + 16d = 21 + a + 9d
     ⇒ 7d = 21
     ⇒ d = 3
Hence, the common difference of the AP is 3.

Mathematics
RS Aggarwal (2015)
Standard X

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