The 17th term of an AP exceeds its 10th term by 21. The common difference of the AP is
(a) 3
(b) 2
(c) −3
(d) −2

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Solution

( a) 3
T₁₀ = a + 9d
T₁₇ = a + 16d

Also, a + 16d = 21 + T₁₀
⇒ a + 16d = 21 + a + 9d
⇒ 7d = 21
⇒ d = 3
Hence, the common difference of the AP is 3.

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