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Question

The 5th term of an arithmetic sequence is 38 and the 9th term is 66. What its 10th term is


A

93

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B

83

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C

73

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D

63

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Solution

The correct option is C

73


x5=28&x9=66

x1+4d=38 & x1+8d=66

Solving

x1+4d=38 x1+8d=66 ––––––––––––– 4d=28 d=7

x1+4(7)=38

x1=3828

x1=10

10th term =x10=x1+9d

=10+9(7)

=10+63

=73


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