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Question

The 5th term of an arithmetic sequence is 38 and the 9th term is 66. What its 10th term is


  1. 93

  2. 83

  3. 73

  4. 63


Solution

The correct option is C

73


x5=28&x9=66

x1+4d=38 & x1+8d=66

Solving

  x1+4d=38      x1+8d=66               –––––––––––––         4d=28             d=7

x1+4(7)=38

x1=3828

x1=10

10th term =x10=x1+9d

=10+9(7)

=10+63

=73

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