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Question

The above bond between carbon atom (1) and carbon atom (2) in compound N=C-CH=$$CH_{2}$$ involves the hybrids as :
                       1  2


A
sp2 and sp2
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B
sp3 and sp
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C
sp  and sp2
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D
sp and sp
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Solution

The correct option is A $$sp^{2}$$ and $$sp ^{2}$$
$$HN=C-CH=CH_2$$
So, carbon atom $$(1)-sp^2$$ hybridised.
Carbon atom $$(2)sp^2$$ hybridised.
(1)Carbon attached to only single bond $$sp^2$$
(2)Carbon attached to single and double bond $$sp^2$$
(3)Carbon attached to single and triple bond $$sp$$

Chemistry

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