CameraIcon

SearchIcon

MyQuestionIcon

1

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Pure Rolling

The accelerat...

Question

The acceleration of ' $m_{1}$ ' and ' $m_{2}$ ' are ' $a_{1}$ ' and ' $a_{2}$ ' then:

A

{a_{1} = a}_{2}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

B

{a_{1} = 2 a}_{2}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

C

2 {a_{1} = a}_{2}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

D

2 {a_{1} \leq a}_{2}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B ${a_{1} = 2 a}_{2}$
Using the constraint for the length of the string we have,
If $m_{2}$ moves down by $x_{2}$ , then $m_{1}$ has to displace by $2 x_{2}$ .
On differentiating it gives us,
$a_{1} = 2 a_{2}$

Suggest Corrections

thumbs-up

0

Similar questions

Q. In the arrangement shown in figure, the relation between acceleration of blocks

m_{1}

m_{2}

| \begin{matrix} A_{1} \end{matrix} | = 3, | \begin{matrix} A_{2} \end{matrix} | = 5,

| \begin{matrix} A_{1} + A_{2} \end{matrix} | = 5

A_{1}

_{1}

A_{2}

_{2}

(2 A_{1} + 3 A_{2}) . (3 A_{1} - 2 A_{2})

is: (report the magnitude).

|_{1} | = 3, |_{2} | = 5

|_{1} +_{2} | = 5

(2_{1} + 3_{2}) . (3_{1} - 2_{2})

_{1}

_{2}

are two two non-collinear unit vectors , then the value of

(_{1} -_{2}) . (\to 2 a_{1} +_{2})

which is not possible is

Q. If pulley shown in the diagram are smooth and massless and

a_{1}

a_{2}

are acceleration of blocks of mass

4 kg

8 kg

respectively, then

View More

Join BYJU'S Learning Program

similar_icon

Related Videos

lock

Rolling

PHYSICS

Watch in App

explore_more_icon

Explore more

Standard XII Physics

Join BYJU'S Learning Program

CrossIcon