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Question

The acceleration of the particle moving in positive x direction with an initial velocity of 20 m/s is 4 m/s2. Its velocity at t=5 sec is

A
22 m/s
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B
40 m/s
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C
30 m/s
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D
25 m/s
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Solution

The correct option is B 40 m/s
Given, a=4 m/s2,u=20 m/s and t=5 sec
Using first equation of motion we have
v=u+at
v=20+4×5=40 m/s
Hence, velocity at t=5 sec is 40 m/s.

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