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Question

The acceleration-time graph of a particle moving along a straight line as shown in figure. The times taken by the particle to acquire its initial velocity is
1900621_9a9bf22f7b3b4978a0ba71f121371444.png


A
4 s
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B
8 s
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C
10 s
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D
5 s
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Solution

The correct option is A $$4\ s$$
slope of graph $$=-3$$
$$a=-3 t+6$$
The area under $$a-t$$ graph show change in velocities
$$\therefore \dfrac{1}{2} OB \times OA=\dfrac{1}{2} AD+CD$$
$$OB \times OB \tan \theta =CD \sqrt{\tan \theta} D$$
$$OB=CD$$
$$2=t_0-2$$
$$t_0=4$$s

1874656_1900621_ans_62df16ab735f463f870f5d984be136bd.png

General Knowledge

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