Question

# The acceleration-time graph of a particle moving along a straight line as shown in figure. The times taken by the particle to acquire its initial velocity is

A
4 s
B
8 s
C
10 s
D
5 s

Solution

## The correct option is A $$4\ s$$slope of graph $$=-3$$$$a=-3 t+6$$The area under $$a-t$$ graph show change in velocities$$\therefore \dfrac{1}{2} OB \times OA=\dfrac{1}{2} AD+CD$$$$OB \times OB \tan \theta =CD \sqrt{\tan \theta} D$$$$OB=CD$$$$2=t_0-2$$$$t_0=4$$sGeneral Knowledge

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