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Question

The active mass of 7.0 g of nitrogen in a 2.0 L container would be:


A
0.25
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B
0.125
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C
0.5
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D
14
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Solution

The correct option is D 0.125
Moles of $$N_2 = \dfrac{7}{28}$$

                      $$ = 0.25 mol$$

Active mass = $$\dfrac{conc. in\ mol}{volume\ in\ L}$$

                  = $$\dfrac {0.25}{ 2} $$

                  = $$ 0.125$$

Hence, option $$B$$ is correct.

Chemistry

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