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Question

The addition of HBr to 1-butene gives a mixture of products (I),(II) and (III):
The mixture consists of :
930527_7092993f4b384b91ab781ded910dfdeb.png

A
(I) and (II) as major and (III) as minor products
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B
(II) as major, (I) and (III) as minor products
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C
(II) as minor, (I) and (III) as major products
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D
(I) and (II) as minor and (III) as major products.
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Solution

The correct option is D (I) and (II) as major and (III) as minor products
CH3CH2CH=CH2HBr−−−−−−−−−−−−−Markovnikov's additionCH3CH2CH|BrCH3exist in 2 enantiomers I and IIMajor product+CH3CH2CH2CH2BrIII (Minor product)

Hence, the mixture consists of (I) and (II) as major and as (III) as minor products.

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