CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

The addition of NaOH to Zn2+ ion gives a white precipitate which on the addition of excess NaOH dissolves the precipitate. In this solution, Zn exists in:

A
Zn2+ form
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
Cationic form
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
Anionic form
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
Both (b) & (c)
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is C Anionic form
Zn2++NaOHZn(OH)2(white ppt)()

Zn(OH)2+NaOH(excess)[Zn(OH)4]2(soluble complex)

flag
Suggest Corrections
thumbs-up
3
similar_icon
Similar questions
View More
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Compounds of Zinc
CHEMISTRY
Watch in App
Join BYJU'S Learning Program
CrossIcon