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Question

The adjacent sides of a parallelogram ABCD measures 34 cm and 20 cm, and the diagonal AC measures 42 cm. Find the area of the parallelogram.

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Solution

In ||gm ABCD, AB= 34 cm, BC= 20 cm
and AC= 42 cm


The diagonal of a parallelogram divides into two triangles equal in area,
Now area of ΔABC,s=a+b+c2=34+20+422=962=48Area=s(sa)(sb)(sc)=48(4834)(4820)(4842)=48×14×28×6=4×4×3×2×7×7×2×2×2×3=7×4×3×2×2=336cm2
Area of ||gm ABCD = 2×area of triangle=2×336=672cm2


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