The amino acid $H_{2} N C H (C O O H) (C H_{2})_{4} N H_{2}$ at low $p H$ exits as:

H_{2} N C H (C O O H) (C H_{2})_{4} N H_{2}

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H_{3} + N C H (C O O H) (C H_{2})_{4} N H_{2}

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H_{3} + N C H (C O O H) (C H_{2})_{4} + N H_{3}

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H_{2} N C H (C O O H) (C H_{2})_{4} + N H_{3}

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Solution

The correct option is C $H_{3} + N C H (C O O H) (C H_{2})_{4} + N H_{3}$
Amino acids can act as an acid as well as because of the presence of carboxyl and amino functional groups. At low $p^{H}$ , the amino acid $H_{2} N C H (C O O H) (C H_{2})_{4} N H_{2}$ exists as ;
$H_{3} N^{+} C H (C O O H) (C H_{2}) (C H_{2})_{4} N H_{3}^{+}$

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