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Question

# The amount of carbon dioxide produced when 40 g of methane reacts with 48 g of oxygen is.

A
44 g
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B
33 g
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C
57 g
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Solution

## The correct option is B 33 gGram molecular mass of methane = 16 g Gram molecular mass of oxygen = 32 g The balanced chemical reaction between methane and oxygen is as follows: CH4(g)+2O2(g)→CO2(g)+2H2O(g) 16 g 64 g 44 g 36 g Thus, 16 g of methane reacts with 64 g of oxygen to produce 44 g of carbon dioxide. The amount of oxygen required to react with 40 g of methane = 6416×40=160 g Since only 48 g of oxygen is present, it will act as a limiting reagent. The amount of carbon dioxide produced by 48 g of oxygen = 4464×48=33 g

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