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The amount of energy released when 20 mL of 0.5 M NaOH are mixed with 100 mL of 0.1 M HCl is x kJ. The heat of neutralisation is : (in kJ mol1)

A
100 x
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B
50 x
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C
+100 x
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D
+50 x
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Solution

The correct option is A 100 x
Find milliequivalents of NaOH and HCl and equate them.
Given, 20 mL of 0.5 M NaOH
100 mL of 0.1 M HCl
Milliequivalents (or millimoles) of NaOH=20×0.5=10
Milliequivalents (or millimoles) of HCl=100×0.1=10
10 milliequivalents on neutralisation given =x kJ heat
1geq (ie, 1000 milliequivalents) will give
=x×100
=100 x kJ heat

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