Question

# The amount of heat released, when 20mL of 0.5M NaOH is mixed with 100mL of 0.1M HCl is x kJ. The best of neutralisation (in kJmol−1) is:

A
100x
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B
50x
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C
+100x
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D
+50x
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Solution

## The correct option is A −100xThe number of moles of NaOH =20 mL1000 mL/L×0.5 mol/L=0.01 mol.The number of moles of HCl =100 mL1000 mL/L×0.1 mol/L=0.01 mol.When 0.01 moles of NaOH neutralises 0.01 moles of HCl, the heat released is x kJ. When 1 mole of NaOH neutralizes 1 mole of HCl, heat released will be x kJ 0.01 mol=100x kJ/molBut since heat is released, negative sign will be introduced. Hence, the answer is −100x kJ/mol.

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