CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

The amount of heat released, when 20mL of 0.5M NaOH is mixed with 100mL of 0.1M HCl is x kJ. The best of neutralisation (in kJmol1) is:

A
100x
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
50x
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
+100x
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
+50x
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is A 100x
The number of moles of NaOH =20 mL1000 mL/L×0.5 mol/L=0.01 mol.
The number of moles of HCl =100 mL1000 mL/L×0.1 mol/L=0.01 mol.
When 0.01 moles of NaOH neutralises 0.01 moles of HCl, the heat released is x kJ.
When 1 mole of NaOH neutralizes 1 mole of HCl, heat released will be x kJ 0.01 mol=100x kJ/mol
But since heat is released, negative sign will be introduced. Hence, the answer is
100x kJ/mol.

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Enthalpy
CHEMISTRY
Watch in App
Join BYJU'S Learning Program
CrossIcon