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Question

The amplitude of a particle executing $$S.H.M$$ with frequency of $$60\ Hz$$ is $$0.01\ m$$. The maximum value of the acceleration of the particle is:


A
144π2 m/s2
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B
144 m/s2
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C
144π2 m/s2
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D
288π2 m/s2
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Solution

The correct option is A $$144{\pi}^{2}\ m/s^{2}$$
Maximum acceleration $$=a \omega^2=a \times  (2 \pi n)^2$$

$$a_m=0.01 \times 4 \times (\pi)^2 \times (60)^2=144{\pi}^{2}\ m/sec$$ 

Physics

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