Question

The amplitude of a particle executing $S.H.M$ with frequency of $60Hz$ is $0.01m$. The maximum value of the acceleration of the particle is:

• A. $144{\pi }^{2}m/s^2$
• B. $144m/s^2$
• C. $\frac{144}{{\pi }^2}m/s^2$
• D. $288{\pi }^{2}m/s^2$

Answer 1

The correct option is A $144{\pi }^{2}m/s^2$

Maximum acceleration $=a{\omega }^2=a\times (2\pi n{)}^2$

$a_m=0.01\times 4\times (\pi {)}^2\times (60{)}^2=144{\pi }^{2}m/sec$