The angle between the lines represented by the equation $x^{2} - 2 p x y + y^{2} = 0$ , is

None of these

The correct option is B

$tan θ = \frac{\pm 2 \sqrt{p^{2} - 1}}{1 + 1} = \pm \sqrt{p^{2} - 1} \Rightarrow θ = s e c^{- 1} p$ .

Suggest corrections

The correct option is B

$tan θ = \frac{\pm 2 \sqrt{p^{2} - 1}}{1 + 1} = \pm \sqrt{p^{2} - 1} \Rightarrow θ = s e c^{- 1} p$ .