The angle between the lines represented by the equation $x^{2} - 2 p x y + y^{2} = 0$ , is

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

No worries! We‘ve got your back. Try BYJU‘S free classes today!

None of these

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B

$tan θ = \frac{\pm 2 \sqrt{p^{2} - 1}}{1 + 1} = \pm \sqrt{p^{2} - 1} \Rightarrow θ = s e c^{- 1} p$ .

Suggest Corrections

Similar questions

The angle between the lines represented by the equation $x^{2} - 2 p x y + y^{2} = 0$ , is

x^{2} - 2 p x y + y^{2} = 0

Angle between the lines represented by the equation $x^{2} + 2 x y s e c θ + y^{2} = 0$ is

x^{2} - 2 p x y - y^{2} = 0

x^{2} - 2 p x y - y^{2} = 0

p q = - 1

x^{2} - 2 p x y - y^{2} = 0

θ,

Explore more