Question

The angle of depression of a car standing on the ground, from the top of a $75\text{m}$ high tower, is ${30}^{\circ }.$. Find the distance of the car from the base of the tower.

Answer 1

In $△ABC$,

$\tan {30}^{\circ }=\frac{75}{B}$

$\Rightarrow \frac{1}{\sqrt{3}}=\frac{75}{B}$

$\Rightarrow B=75\sqrt{3}\text{m}$

So the distance of the base of the tower to the car is $75\sqrt{3}\text{m}$.