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Question

The angle which a vector ^i^j+2^k makes with x-axis is

A
60o
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B
120o
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C
150o
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D
tan1(12)
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Solution

The correct option is B 120o
Let A=^i^j+2^k and vector representing y - axis be B=^j.
We know that cosβ=AB|A||B|=1(1)2+(1)2+(2)2=12
β=120o

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