Question

# The angular momentum of an electron in Bohr's hydrogen atom whose energy is $$-3.4 eV$$, is

A
5h2π
B
h2π
C
hπ
D
2h3π

Solution

## The correct option is B $$\dfrac{h}{\pi}$$Energy of electron in nth orbit of hydrogen atom$$E_n = - \dfrac{13.6}{n^2} eV$$$$\Rightarrow 3.4 = - \dfrac{13.6}{n^2} \Rightarrow n^2 = 4$$or, $$n = 2$$Angular momentum of electron,$$L = \dfrac{nh}{2 \pi} = \dfrac{2h}{2 \pi} = \dfrac{h}{\pi}$$Physics

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