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Question

The angular momentum of an electron in Bohr's hydrogen atom whose energy is $$-3.4 eV$$, is


A
5h2π
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B
h2π
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C
hπ
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D
2h3π
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Solution

The correct option is B $$\dfrac{h}{\pi}$$
Energy of electron in nth orbit of hydrogen atom
$$E_n = - \dfrac{13.6}{n^2} eV$$
$$\Rightarrow 3.4 = - \dfrac{13.6}{n^2} \Rightarrow n^2 = 4$$
or, $$n = 2$$
Angular momentum of electron,
$$L = \dfrac{nh}{2 \pi} = \dfrac{2h}{2 \pi} = \dfrac{h}{\pi}$$

Physics

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