The angular rim of a wheel $400$ cm in diameter has a velocity of $1600 {c m s}^{- 1}$ . The angular velocity of the wheel is:

8 r a d s^{- 1}

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4 r a d s^{- 1}

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12 r a d s^{- 1}

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16 r a d s^{- 1}

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Solution

The correct option is B $8 r a d s^{- 1}$
$R = 200 c m$
$V = 16 m / s$
$ω =$ $\frac{V}{R}$
$= \frac{16}{200} \times 100 = 8 r a d / s$

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