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Angular Velocity

The angular s...

Question

The angular speed of seconds needle in a mechanical watch is

\frac{π}{30} r a d / s

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2 π r a d / s

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π r a d / s

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\frac{60}{π} r a d / s

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Solution

The correct option is D $\frac{π}{30} r a d / s$
It is known that $ω = \frac{2 π}{T}$
For watch $T = 60 s$
$ω = \frac{2 π}{T} = \frac{2 π}{60} = \frac{π}{30} r a d / s$

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