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Question

The angular velocity of a point on the rim of a rotating wheel is given by ω=(46t+3t2) rad/s. What is the average angular acceleration for the time interval t=2 s to t=4 s ?

A
12 rad/s2
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B
6 rad/s2
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C
24 rad/s2
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D
3 rad/s2
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Solution

The correct option is A 12 rad/s2
As we know,
Average angular acceleration aavg=ΔωΔt=ωfωitfti
=ω(t=4 s)ω(t=2 s)42
From ω=(46t+3t2) rad/s
ω(t=2 s)=(46×2+3×22)
=4 rad/s
ω(t=4 s)=(46×4+3×42)
=28 rad/s

aavg=28 rad/s4 rad/s42
aavg=12 rad/s2

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