Question

The approximate value of quantum number ${}^{\prime }n{}^{\prime }$ for the circular orbit of hydrogen of $0.0001mm$ in diameter is

• A. $1000$
• B. $60$
• C. $10000$
• D. $31$

Answer 1

The correct option is D $31$

For $d=0.0001mm={10}^{-7}m=1000A$
$r=0.529\frac{n^2}{Z}$
For hydrogen, $Z=1$
$500=0.529n^2$
$n=30.74$