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Question

The approximate value of 533 is

A
2.0125
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B
2.1
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C
2.01
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D
3.258
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Solution

The correct option is A 2.0125
Let y=x1/5 where x=32 and Δx=+1
Now, y=x1/5
Differentiating both sides wrt x,
dydx=15x4/5
Using Δy=dydxΔx
Δy=15(x4/5)Δx
Putting values,
Δy=15(32)4/5(1)
Or, Δy=15×25×4/5=0.0125
We know,
Δy=f(x+Δx)f(x)
Or, Δy=(x+Δx)1/5x1/5
0.0125=(32+1)1/5(32+1)1/5
Or, 0.125=331/525×1/5
Or, 2.0125=331/5
So, the approximate value of 533 is 2.0125

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