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Question

The area bounded by the curve x2+2x+y3=0, the xaxis and the tangent at the point, where it meets the yaxis is

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Solution

The equation of the curve is x2+2x+y3=0
or x2+2x+1+y31=0 (add and subtract 1)
y4=(x+1)2
The curve meets the yaxis at (0,3) and the xaxis at (3,0) and (1,0)
The tangent at (0,3) is y3=2(x0)
The required area=area of OABthe shaded area(OCB)
=12.32.310(4(x+1)2)dx
=94[4x(x+1)33]10
=94[(483)+13]
=944+73=712.sq.unit
954421_1043275_ans_9d8d6c0bc20643ca82759d25f108f8b6.png

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