The area of a rectangular field is given as $300$ square metres. It is also given that the breadth of the field is $3$ metres more than its length. Can this information be expressed mathematically as a Quadratic Equation. If yes, what would be the resulting Quadratic Equation?

Open in App

Solution

Let length be $l$ m
breadth be $(l + 3)$ m
$l (l + 3) = 300 l^{2} + 3 l - 300 = 0$

Suggest Corrections

Similar questions

Q. Represent the given situation in the form of a quadratic equation: The length of a rectangular park (in metres) is one more than twice its breadth and its area is

528 m

^{2}

The product of two consecutive even numbers is $120$ . Can you express this information in the form of a Quadratic Equation? If yes, what would be the resulting Quadratic Equation?

For a rectangular field of area 3 sq. units, the length is one unit more than twice the breadth ‘x’. The quadratic equation representing the situation is:

Q. The length of a rectangular field is

5

metres less than twice the breadth. If its area is

700

square metres, then the perimeter (in metres) of the field is

The area of a rectangle is 460 square metres. If the length is 15 $%$ more than the breadth, what is the breadth of the rectangular field?

Join BYJU'S Learning Program

The area of a rectangular field is given as 300 square metres. It is also given that the breadth of the field is 3 metres more than its length. Can this information be expressed mathematically as a Quadratic Equation. If yes, what would be the resulting Quadratic Equation?

Let length be l m breadth be (l+3) ml(l+3)=300l2+3l−300=0

The area of a rectangular field is given as $300$ square metres. It is also given that the breadth of the field is $3$ metres more than its length. Can this information be expressed mathematically as a Quadratic Equation. If yes, what would be the resulting Quadratic Equation?

Let length be $l$ m
breadth be $(l + 3)$ m
$l (l + 3) = 300 l^{2} + 3 l - 300 = 0$