The area of a sector (in $c m^{2}$ )of a circle with radius 6 cm if angle of the sector is $70^{\circ}$ will be __ . ( Take $π$ = $\frac{22}{7}$ )

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Solution

Given that radius r = 6 cm
$θ$ = $70^{\circ}$
Area of sector of an angle $θ$ with radius r = $\frac{70}{360}$ × $\frac{22}{7}$ × $6^{2}$
= 22 $c m^{2}$

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The area of a sector (in cm2 )of a circle with radius 6 cm if angle of the sector is 70∘ will be __ . ( Take π = 227)

Given that radius r = 6 cm θ = 70∘ Area of sector of an angle θ with radius r = 70360 × 227 × 62 = 22 cm2

The area of a sector (in $c m^{2}$ )of a circle with radius 6 cm if angle of the sector is $70^{\circ}$ will be __ . ( Take $π$ = $\frac{22}{7}$ )

Given that radius r = 6 cm
$θ$ = $70^{\circ}$
Area of sector of an angle $θ$ with radius r = $\frac{70}{360}$ × $\frac{22}{7}$ × $6^{2}$
= 22 $c m^{2}$