The area of a sector of a circle of radius 2 cm is π cm2. Find the angle contained by the sector.
Area of a sector subtending angle θ degrees at the centre of a circle of radius r is given by πr2×θ360o.
Now, πr2×θ360o=π
⇒π×22×θ360o=π
⇒θ=90o
Therefore, the angle subtended at the centre of the circle is 90 degrees.