Question

The area of a square whose two sides lie on lines x+y=1 and x+y+2=0 will be .

• A. $\frac{9}{2}sq.units$
• B. $\frac{9}{4}sq.units$
• C. $\frac{3}{2}sq.units$
• D. $\frac{3}{4}sq.units$

Answer 1

The correct option is A $\frac{9}{2}sq.units$

The given lines are parallel to each other.
Hence, the distance between the parallel sides = the length of the side of the square =
$\left(\frac{2-(-1)}{\sqrt{1^2}+\sqrt{1^2}}\right|=\frac{3}{\sqrt{2}}$
$\therefore$ The area of the square = $(\frac{3}{\sqrt{2}}{)}^2=\frac{9}{2}sq.units$