Question

The area of an equilateral triangle whose side is 8 cm, is

• A. 64 $c{m}^2$
• B. $16\sqrt{3}$ $c{m}^2$
• C. 21.3 $c{m}^2$
• D. $4\sqrt{3}$ $c{m}^2$

Answer 1

Answer: (B)

$16\sqrt{3}$ $c{m}^2$

Given, side of an equilateral triangle $=8cm$

Area of an equilateral triangle with length of side $a=\frac{\sqrt{3}}{4}{a}^2$

$\therefore$ area of this equilateral triangle $=\frac{\sqrt{3}}{4}\times 8^2=16\sqrt{3}{cm}^2$