Question

The area of rhombus is $96c{m}^2$. If one of its diagonals is $16cm$ then what will be the side of the rhombus?

Answer 1

Area of rhombus =$96sqcm$

Area=$\frac{1}{2}\times d_1\times d_2$

Given that

$d_1=16cm$

$d_2=?$

Hence

$96=\frac{1}{2}\times d_1\times d_2$

$d_2=\frac{96}{8}$

$d_2=12cm$