Question

# The area of the base of a rectangle tank is $$6500\ cm^{2}$$ and the volume of water contained in it is $$2.6$$ cubic metre. Find the depth of water in the tank.

Solution

## The water tank is in the form of a cuboid.Given: Area of a base of rectangular tank$$=l\times b=6500{cm}^{2}$$Volume of water contained in it$$=lbh=2.6{m}^{3}$$Depth of the water$$=$$height of the tank$$=h=\dfrac{lbh}{lb}=\dfrac{2.6{m}^{3}}{6500{cm}^{2}}$$We know that $$1\ m=100 \ cm$$$$\Rightarrow 1{m}^{3}={\left(100\ cm\right)}^{3}$$$$\therefore h=\dfrac{2.6\times 100\times 100\times 100 {cm}^{3}}{6500{cm}^{2}}$$$$=400‬$$cm$$\therefore$$ Depth of water in the tank$$=400‬$$cmMathematics

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