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Question

The area of the base of a rectangle tank is $$6500\ cm^{2}$$ and the volume of water contained in it is $$2.6$$ cubic metre. Find the depth of water in the tank.


Solution

The water tank is in the form of a cuboid.
Given: Area of a base of rectangular tank$$=l\times b=6500{cm}^{2}$$
Volume of water contained in it$$=lbh=2.6{m}^{3}$$
Depth of the water$$=$$height of the tank$$=h=\dfrac{lbh}{lb}=\dfrac{2.6{m}^{3}}{6500{cm}^{2}}$$
We know that $$1\ m=100 \ cm$$
$$\Rightarrow 1{m}^{3}={\left(100\ cm\right)}^{3}$$
$$\therefore h=\dfrac{2.6\times 100\times 100\times 100 {cm}^{3}}{6500{cm}^{2}}$$
$$=400‬$$cm
$$\therefore$$ Depth of water in the tank$$=400‬$$cm

Mathematics

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