We know that the area of the parallelogram is equal to the magnitude of the cross product of given vectors.
∣∣=^i(2+9)+^j(6−1)+^k(−3−4)=11^i+5^j−7^kSo area of parallelogram :|→A×→B|=√112+52+(−7)2=√195sq.unit
The two adjacent sides of a parallelogram are 2^i−4^j+5^k and ^i−2^j−3^k. Find the unit vector parallel to its diagonal. Also, find its area.