The area of the triangle A B C- in which a -1- b -2- - C -600- isA- 4 sq unitB- 1 - 2 sq unitC- -3-2 sq unitD- -3 sq unit

The correct option is C sq unit Given that, a=1, b=2, ∠ C=60^0 ∴ Area of triangle =1/2ab sin C =1/2× 1 × 2 × sin 60^0 =1/2× 2 ×√(3)/2 =√(3)/2sq unit ...

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Standard XII

Mathematics

Sine Rule

The area of t...

Question

The area of the triangle ABC, in which a = 1, b = 2, $∠$ $C = 60^{0},$ is

4 sq unit

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1/2 sq unit

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sq unit

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Solution

The correct option is C
sq unit

Given that, $a = 1, b = 2, ∠ C = 60^{0}$
$∴ A r e a o f t r i a n g l e = \frac{1}{2} a b s i n C$
$= \frac{1}{2} \times 1 \times 2 \times s i n 60^{0} = \frac{1}{2} \times 2 \times \frac{\sqrt{3}}{2}$
$= \frac{\sqrt{3}}{2} s q u n i t$

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The area of the triangle ABC, in which a = 1, b = 2, ∠ C=600, is

The correct option is C sq unit Given that, a=1, b=2,∠C=600 ∴Area of triangle=12ab sin C =12×1×2×sin600=12×2×√32 =√32sq unit

The area of the triangle ABC, in which a = 1, b = 2, $∠$ $C = 60^{0},$ is

The correct option is C
sq unit

Given that, $a = 1, b = 2, ∠ C = 60^{0}$
$∴ A r e a o f t r i a n g l e = \frac{1}{2} a b s i n C$
$= \frac{1}{2} \times 1 \times 2 \times s i n 60^{0} = \frac{1}{2} \times 2 \times \frac{\sqrt{3}}{2}$
$= \frac{\sqrt{3}}{2} s q u n i t$