Question

The average depth of indian ocean is about 3000 m. The frictional compression, $\frac{\Delta V}{V}$ of work at the bottom of the ocean ( give that the bulk modulus of the water $2.2\times {10}^9$ ${Nm}^{-2}$ and $g=10m{s}^{-2}$ is

• A. $0.82\%$
• B. $0.91\%$
• C. $1.36\%$
• D. $1.24\%$

Answer 1

The correct option is C $1.36\%$

$\left|B\right|=\frac{dp}{\left(\frac{dv}{v}\right)}$

$\Rightarrow 2.2\times {10}^9=\frac{\rho gH}{\left(\frac{dv}{v}\right)}$

$\Rightarrow \left(\frac{dv}{v}\right)=\frac{1000\times 10\times 3000}{2.2\times {10}^9}$

$=\frac{dv}{v}\times 100$

$=\frac{30}{262}$

$=\frac{15}{11}$

$[=1.36\%]$

Hence,

option $C$ is correct answer.