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Question

The average kinetic energy of a gas molecule at 27 is 6.21×1021J. The average kinetic energy at 227 will be
 



A

9.35×1021J
 

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B

10.35×1021J
 

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C

11.35×1021J
 

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D

12.35×1021J

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Solution

The correct option is B

10.35×1021J
 


E=12kT.Thus 6.21×1021=12k×(273+27)                         150kgiving k=6.21×1021150. Therefore at 227, the value of E isE=12×6.21×1021150(273+227)      =10.35×1021J
Hence, the correct choice is (b).


Physics

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