Question

# The average kinetic energy of an ideal gas per molecule in SI units at $$25^0C$$ will be:

A
6.17×1021 JK1
B
6.17×1021 kJK1
C
6.17×1020 JK1
D
7.16×1021 JK1

Solution

## The correct option is A $$6.17\times 10^{-21} \ JK^{-1}$$The average kinetic energy of molecules is measured by taking the temperature. It is calculated as $$\dfrac { 3 }{ 2 } KT$$Where K is Boltzmann constant $$=1.38\times10^{-23} JK^{-1}$$T is temperature is $$25+273=298K$$Avg. kinetic energy will be $$\dfrac { 3 }{ 2 } \times1.38\times{ 10 }^{ -23 }\times298=6.168\times{ 10 }^{ -21 }JK^{-1}$$Option A is correct.Physics

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