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Question

The average kinetic energy of an ideal gas per molecule in SI units at $$25^0C$$ will be:


A
6.17×1021 JK1
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B
6.17×1021 kJK1
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C
6.17×1020 JK1
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D
7.16×1021 JK1
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Solution

The correct option is A $$6.17\times 10^{-21} \ JK^{-1}$$
The average kinetic energy of molecules is measured by taking the temperature. 

It is calculated as $$\dfrac { 3 }{ 2 } KT$$

Where K is Boltzmann constant $$=1.38\times10^{-23} JK^{-1}$$

T is temperature is $$25+273=298K$$

Avg. kinetic energy will be $$\dfrac { 3 }{ 2 } \times1.38\times{ 10 }^{ -23 }\times298=6.168\times{ 10 }^{ -21 }JK^{-1}$$

Option A is correct.

Physics

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