The average weight of $14$ students was calculated as $71$ . But it was later found that the weight of one student had been wrongly entered as $42$ instead of $56$ and of another as $74$ instead of $32$ . The correct average is

75

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80

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68

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69

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Solution

The correct option is D $69$
Required average $= \frac{14 \times 71 + 56 - 42 + 32 - 74}{14}$
$= \frac{966}{14} = 69$ .

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The average weight of 14 students was calculated as 71. But it was later found that the weight of one student had been wrongly entered as 42 instead of 56 and of another as 74 instead of 32. The correct average is

The correct option is D 69Required average =14×71+56−42+32−7414=96614=69.

The average weight of $14$ students was calculated as $71$ . But it was later found that the weight of one student had been wrongly entered as $42$ instead of $56$ and of another as $74$ instead of $32$ . The correct average is

The correct option is D $69$
Required average $= \frac{14 \times 71 + 56 - 42 + 32 - 74}{14}$
$= \frac{966}{14} = 69$ .