Question

The base of a container measures $15\times 20$cm. It is placed on a table top. If the weight of the container is 60 N, what is the pressure exerted by the container on the table top?

Answer 1

Area of the base of the container, A = 15 cm $\times$ 20 cm

= $\frac{15}{100}$ $\times$ $\frac{20}{100}$

= $\frac{300}{10000}$

Force = weight = 60 N

Pressure = $\frac{F}{A}$

= $\frac{60\times 10000}{300}$

= 2000 Pa