The best reagent for converting, 2-phenylpropanamide into 1-phenylethanamine is:

excess

H_{2} / P t

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N a O H / B r_{2}

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N a B H_{4} /

methanol

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L i A l H_{4} /

ether

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Solution

The correct option is A $N a O H / B r_{2}$
By Hoffmann bromamide degradation reaction, tha amine formed contains one carbon less than that present in the amide.

$C H_{3} - C_{6} H_{5} | C H - C O N H_{2} + B r_{2} + 4 N a O H \to C H_{3} - C_{6} H_{5} | C H - N H_{2} + N a_{2} C O_{3} + 2 N a B r + 2 H_{2} O$
2-phenylpropanamide 1-phenylethanamine

Option B is correct.

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