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Nuclear Fusion

The binding e...

Question

The binding energies of nuclei X and Y are $E_{1}$ and $E_{2}$ , respectively. Two atoms of X fuse to give one atom of Y and an energy $Q$ is released. Then,

Q = 2 E_{1} - E_{2}

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Q = E_{2} - 2 E_{1}

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Q < 2 E_{1} - E_{2}

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Q > E_{2} - 2 E_{1}

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Solution

The correct option is A $Q = E_{2} - 2 E_{1}$
Given that two atoms of $X$ fuse to give one atom of $Y$ .
Final energy $= E_{2}$
Initial energy $= 2 E_{1}$ (two atoms of X)
Hence, difference in binding energies is $= E_{2} - 2 E_{1}$
Given that $Q$ is released.
Hence, $E_{2} - 2 E_{1} = Q$

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Similar questions

The binding energies of nuclei X and Y are E₁ and E₂ respectively. Two atoms of X fuse together to give one atom of Y and some amount of energy,Q is released. Then

Q. The binding energies of nuclei

X

and

Y

are

E_{1}

and

E_{2}

respectively. Two atoms of

X

fuse to give one atom of

Y

and an energy

Q

is released. Then

\frac{N_{0}}{2}

atoms of

X (g)

are converted into

X^{+} (g)

by absorbing

E_{1}

energy.

2 N_{0}

atoms of

X (g)

are converted into

X^{-} (g)

by releasing

E_{2}

energy. Calculate the ionisation enthalpy and electron gain enthalpy of

X (g)

per atom.

A_{0} / 2

atoms of

X (g)

are converted into

X^{+} (g)

by absorbing energy

E_{1}

A_{0} / 2

X^{+} (g)

are converted into

X^{-} (g)

with the release of energy,

E_{2}

. Hence the ionisation energy and the electron affinity of

X (g)

are repectively _____ and _______.

Q. If

e_{1}

and

e_{2}

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(2 e_{1} - 5 e_{2}) . (3 e_{1} + e_{2})

| e_{1} + e_{2} | = \sqrt{3} .

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The binding energies of nuclei X and Y are E1 and E2, respectively. Two atoms of X fuse to give one atom of Y and an energy Q is released. Then,

The correct option is A Q=E2−2E1Given that two atoms of X fuse to give one atom of Y.Final energy =E2Initial energy =2E1 (two atoms of X)Hence, difference in binding energies is =E2−2E1Given that Q is released.Hence, E2−2E1=Q

The binding energies of nuclei X and Y are $E_{1}$ and $E_{2}$ , respectively. Two atoms of X fuse to give one atom of Y and an energy $Q$ is released. Then,

The correct option is A $Q = E_{2} - 2 E_{1}$
Given that two atoms of $X$ fuse to give one atom of $Y$ .
Final energy $= E_{2}$
Initial energy $= 2 E_{1}$ (two atoms of X)
Hence, difference in binding energies is $= E_{2} - 2 E_{1}$
Given that $Q$ is released.
Hence, $E_{2} - 2 E_{1} = Q$