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Question

The binding energy per nucleon for 6C12 nucleons is 7.68MeV and that for 6C13 is 7.47 MeV. Calculate the energy required to remove a neutron from 6C13 nucleons.

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Solution

Given data:
Binding energy per nucleon of
6C13=7.47MeV
Binding energy per nucleon of 6C12=7.68MeV
Binding energy of neutron=?
Solution:
We can write the reaction as:
6C136C12+0n1
Total binding energy of 6C13=7.47×13=97.11MeV
Total binding energy of 6C12=7.68×12=92.16MeV
Total binding energy of the reactant= Total binding energy of the product
97.11MeV=92.16MeV+Binding energy of a neutron.
Binding energy of a neutron=97.1192.16
=4.95MeV.

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