Question

The binding energy per nucleon of ${}^{16}O$ is $7.97MeV$ and that of ${}^{17}O$ is $7.75MeV$. The energy in MeV required to remove a neutron from ${}^{17}O$ is:

• A. $3.52$
• B. $3.64$
• C. $4.23$
• D. $7.86$
• E. $1.68$

Answer 1

Answer: (C)

$4.23$

BE per nucleon ${}^{16}O=7.97MeV$
BE per nucleon ${}^{17}O=7.75MeV$
${}^{17}O\to {}_0{n}^1+{}^{16}O$
Energy required to remove neutron
$=17\times 7.75-16\times 7.97$
$=4.23MeV$.