The binomial coefficients which are in decreasing order are

^{15} C_{5},^{15} C_{6},^{15} C_{7}

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^{15} C_{10},^{15} C_{9},^{15} C_{8}

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^{15} C_{6},^{15} C_{7},^{15} C_{8}

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^{15} C_{7},^{15} C_{6},^{15} C_{5}

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Solution

The correct option is D $^{15} C_{7},^{15} C_{6},^{15} C_{5}$
$^{15} C_{5} = 3003;^{15} C_{6} = 5005$

$^{15} C_{7} = 6435;^{15} C_{8} =^{15} C_{7} = 6435$

$^{15} C_{9} =^{15} C_{6} = 5005$

$^{15} C_{10} =^{15} C_{5} = 3003$

Since $6435 < 5005 < 3003$

Therefore, $^{15} C_{7} <^{15} C_{6} <^{15} C_{5}$

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Similar questions

In the expansion of the binomial expansion (a + b)ⁿ, which of the following is incorrect ?

C_{0}, C_{1}, C_{2}, . . . ., C_{n}

n

\frac{C_{1}}{2} + \frac{C_{3}}{4} + \frac{C_{5}}{6} + . . . . =

{(\sqrt{x} + \frac{1}{2 \cdot \sqrt[4]{x}})}^{n}, n \in N

x .

{(1 + x)}^{n}

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