CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

The blades of a windmill sweep out a circle of area A.
(a) If the wind flows at a velocity v perpendicular to the circle, what is the mass of the air passing through it in time t?
(b) What is the kinetic energy of the air?
(c) Assume that the windmill converts 25% of the winds energy into electrical energy, and that A = 30 m2, v = 36 km/h and the density of air is 1.2 kg m3. What is the electrical power produced?

Open in App
Solution

(a)
Density of air =ρ kg/m3
Time taken = t sec
Velocity of air = v m/s
Mass of the air = density × volume =ρAvt
(b)
KE=12mv2
=12(ρAvt)v2
=12(ρAv3t)

(c)
Velocity, v= 36 km/hr = 10 m/s
ρ=1.2kg/m3
A=30m2
Work done = change in kinetic energy
=12×1.2×30×103tNm
=18000tJ
Power = work/t=18000W
Efficiency = 25%
Actual power=18000×25/100=4500W

379722_419857_ans_96778b2ca20148659c65149e90a0b0c8.PNG

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Kinetic Energy
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon