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Question

# The bob of a simple pendulum is released when its string is horizontal. If kinetic energy of bob is 0.1732 J when string makes an angle 30° with horizontal, then its kinetic energy when string makes an angle 60° with horizontal is :

A
0.2 J
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B
0.3 J
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C
0.4 J
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D
0.5 J
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Solution

## The correct option is D 0.3 JLet the length of string be l mWhen string makes 30∘ with horizontal then the vertical drop of pendulum is lsin(30∘)=l/2 mK.E.gain=P.E.loss⇒mgl2=0.1732 J=>mgl=0.1732×2 JWhen string makes 60∘ with horizontal then the vertical drop of pendulum is lsin(60∘)=l√32 mK.E Gain = P.E. loss = mgl√32=0.1732×2×√32 = 0.3 J

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