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Question

The bob of a stationary pendulum is given a sharp hit to impart it a horizontal speed of 3 gl . Find the angle rotated by the string before it becomes slack.


Solution

V=3gl

12mv212mu2=mgh

v2=u22g(l+l cos θ)          ...(i)

Again, mv2l=mg cos θ

v2=lg cos θ

From equation (i) and (ii), we get,

3gl2gl2gl cos θ=gl cos θ

3 cos θ=1

θ=cos1(13)

=cos1(13)

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