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Question

The bond order in $$\displaystyle { O }_{ 2 }^{ - }$$ ion is:


A
2
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B
1
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C
2.5
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D
1.5
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Solution

The correct option is D 1.5
The molecular configuration of $$\displaystyle { O }_{ 2 }^{ - }$$ is as
$$\displaystyle \sigma 1{ s }^{ 2 },{ \sigma  }^{ \ast  }1{ s }^{ 2 },\sigma 2{ s }^{ 2 },{ \sigma  }^{ \ast  }2{ s }^{ 2 },{ \sigma  }^{ \ast  }2{ p }_{ z }^{ 2 },\pi 2{ p }_{ y }^{ 2 }\approx \pi 2{ p }_{ z }^{ 2 },{ \pi  }^{ \ast  }2{ p }_{ y }^{ 2 }\approx { \pi  }^{ \ast  }{ 2p }_{ z }^{ 1 }$$
Bond order $$\displaystyle =\frac { { N }_{ b }-{ N }_{ a } }{ 2 } $$
$$\displaystyle =\frac { 10-7 }{ 2 } $$
$$\displaystyle \therefore $$ Bond order = 1.5

Chemistry

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