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Question

The brake applied to a car produce an acceleration of 6m/s^2 in opposite direction. If the car stops in 2 seconds calculate the distance travelled


Solution

Acceleration a = -6 m/s^2
Time t = 2 s
Final velocity v = 0 m/s

Let initial velocity be u.
Let distance be s.

v = u + at
So, 0 = u + (-6)(2)
So, u = 12 m/s

Now, s = ut + (1/2) at^2
So, s = 12(2) + (1/2)(-6)(2^2)
So, s = 24 - 12
So, s = 12 m

Thus, distance travelled is 12 m

 

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